A charged particle (q = –8.0 mC), which moves in a region where the only force acting on the particle is an electric force, is released from rest at point A. At point B the kinetic energy of the particle is equal to 4.8 J. What is the electric potential difference VB – VA? Group of answer choices –0.80 kV +0.80 kV –0.48 kV –0.60 kV +0.60 kV

The electric potential difference between two given points is

Explanation:

Here we know that work done by electrostatic force = change in its kinetic energy

   work done=

since Δv = =

Δv == =

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explanation:

the answer is the first electromagnet (a). this is because it has more coils around the ferromagnetic material. increasing the number of coils increases the surface area in which the metal interacts with the current in the coil. this enables more atoms in the metal to become aligned hence becoming more magnetized.