A 70.0 kg ice hockey goalie, originally at rest, has a 0.110 kg hockey puck slapped at him at a velocity of 43.5 m / s . Suppose the goalie and the puck have an elastic collision, and the puck is reflected back in the direction from which it came. What would the final velocities of the goalie and the puck be in this case

0.06824 m.s for each  - puck and goalie

Explanation:

Mass of puck=m1= 0.11 kg

Mass of goalie = m2 = 70 kg

Initial vel of puck=V1i= 43.5 m/s

Initial vel of goalie = Vi2= 0 m/s

V1f = final velocity of puck

Vf2= final velocity of goalie

Because goalie hits the puck , the final velocity of both is equale i-e Vf1=Vf2=V

Using constant momentum rule;

m1V1i+m2V2i = m1 V1f+m2V2f

==> m1 V1i +0 = m1 V1f+m2V2f

==>m1 V1i  = (m1+m2) V

==> V= m1V1i ÷ (m1+m2) = 0.11 × 43.5 ÷ (0.11+70)= 4.785÷ 70.11 m/s = 0.06824 m/s

d.7.5cm is your answer

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day