Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which is proportional to speed-squared. For a certain car with a weight of 12000 N, the total resistant force F is given by F = 300 + 1.8v2, with F in newtons and v in meters per second. Calculate the power (in horsepower) required to accelerate the car at 0.90 m/s2 when the speed is 84 km/h.

Explanation:

Let assume that vehicle is moving on a horizontal surface and the vehicle mass is 1500 kg. The equation for the power needed to accelerate the car is:

The equivalent engine force needed to accelerate the car is derived from the following equation of equilibrium:

The power required at a given velocity is:

The output at is:

kinetic

i'm so sorry if this is wrong i'm only in 6th grade xd

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft