The scale on the ω axis is set by ωs = 6.0 rad/s. (a) What is the magnitude of the rod’s angular acceleration? (b) At t = 4.0 s, the rod has a rotational kinetic energy of 1.60 J. What is its kinetic energy at t = 0?

a. 1.5rad/s

b. 0.40J

Explanation:

a. Angular acceleration is obtained by determining the gradient  of the straight line.

-The graph perfectly cuts two points[4,4], [2,1]:

#The line's gradient is 1.5

Hence, the rod's angular acceleration is 1.5rad/s

b. Let at t=0, the angular velocity be and at .

#Rotational kinetic energy is determined using the formula:

#Equate the expression to the energy value given:

Hence, the kinetic energy at t=o is 0.40J

answer would be d.) i hope this

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