A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum output gauge pressure must the pump generate to make the water reach the nozzle at ground level, 75 m above the pump?

The Required pressure for this situation is P= 735000Pa

Explanation:

In Determining the required pressure in this situation we use two equations

First one is

F = mg = (ρhA)g

And Second one is

P = = (ρhAg)/A Where P is pressure

We get

P = ρhg  

since g = 9.8 m/s and h is given that is 75m and ρ =

so

P = (9.8 m/s)()(75) we get

P = 735000 Pa

force tends to be low and long diustance masses are high

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west