580 nm light shines on a double slit with d=0.000125 m. What is the angle of the third dark interference minimum(m=3)?

0.796 degree

Explanation:

We are given that

Wavelength=

We have .to find the angle of the third dark interference minimum=3

Using the formula

Hence, the angle of the third dark interference minimum=0.796 degree

we can see how the government has failed them.

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000