The large blade of a helicopter is rotating in a horizontal circle. The length of the blade is 6.30 m, measured from its tip to the center of the circle. Find the ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 4.43 m from the center of the circle.

Explanation:

Given:

R1 = 6.3 m

R2 = 4.43 m

Centripetal acceleration, ac = v^2/R

Where,

v = tangential velocity

R = radius if the motion

ac1 = v1^2/R1

ac2 = v2^2/R2

R1 × ac1 = ac2 × R2

6.3 × ac1 = ac2 × 4.43

1.42 × ac1 = ac2

Ratio of ac1 to ac2,

1 : 0.7.

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