Draw the force vector starting at the black dot. The location, orientation, and length of the vector will be graded. You can move the vectors F⃗ 1F→1 and F⃗ 2F→2 to construct the required vector, but be sure to return them into their initial positions before submitting the answer.

F3 is the equilibrant force equal in magnitude to the resultant between F1 and F2 but opposite in direction to it.

Explanation:

Given the diagram, the force F3 to make the body remain at rest or in equilibrium is the equilibrant force, this force is equal in magnitude to the resultant Fr between F1 and F2 but opposite in direction to it.

See attachment for diagram of forces.

The resultant force;

Fr =√ (F1)² + (F2)²...(1) [diagram a]

Therefore the length of F3 is Fr

F3 = -Fr

The direction (diagram b) of the resultant force Fr is given by

∆ = acrtan[(F1/F2)]

The direction of F3 is [90 + arctan(F1/F2)]

As seen in the diagram (d), the location of the force is in the fourth quadrant.

good looking response

the answer is 12 as i may remember

: )