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Physics, 17.03.2020 05:17 jngonzo1226

A force F= (6.70 N)i + (5.60 N)j + (6.60 N)k act on a 9.80 kg mobile object that moves from an initial position of di = (9.10 m)i + (5.30 m)j + (6.70 m)k to a final position of df = (8.00 m)i + (9.70 m)j + ( 3.30 m)k in 5.90 s.

Find (a) the work done on the object by the force in the 5.90 s interval, (b) the average power due to the force during that interval.

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