Choose the situation below in which the force applied is the greatest.
A) Steve put in 50 J of work moving a box 50 meters.
B) Doing 400 J of work, Penny pushed her cat 80 meters.
C) Samantha did 365 J of work dragging a wagon across 73 meters of lawn.
Eliminate
D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.

maximum work is done in the case

D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.

Explanation:

As we know that the Work done is product of force and displacement

So we have

A) Steve put in 50 J of work moving a box 50 meters.

So here we have

50 = F . 50

F = 1 N

B) Doing 400 J of work, Penny pushed her cat 80 meters.

So here we have

400 = F . 80

F = 5 N

C) Samantha did 365 J of work dragging a wagon across 73 meters of lawn.

So here we have

365 = F . 73

F = 5 N

D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.

So here we have

144 = F . 16

F = 9 N

So maximum work is done in the case

D) Clark pushed a crate from the chair, 16 meters across the room, doing 144 J of work.

b

step-by-step explanation: a third of 24 is 8, 8 times 3 is 24 so 8 - 2 would be 6