If the coefficient of static friction between your friend and the car seat is 0.500 and you keep driving at a constant speed of 21.0 m/sm/s , what is the maximum radius you could make your turn and still have your friend slide your way?

90m

Explanation:

Let g = 9.8 m/s2. The friction is the product of normal force and its coefficient, and normal force is equal to gravity

The acceleration caused by friction, according to Newton's 2nd law:

For the friend to slide over, then the centripetal acceleration must be equal to friction acceleration.

Since you are driving at a constant speed of 21 m/s, then your maximum radius of curvature can be calculated using the following formula:

the answer to this question is 60 n

well clustered together.

points close on a scatter diagram