A ball with a mass of 3 kg moving at 5 m/s collides with a 9 kg ball at rest. After the collision, the impacting (3 kg) ball bounces back at a speed of 2.5 m/s. How fast does the 9 kg ball move and in what direction

The second ball moves with 0.83 m/s forward.

Explanation:

Given;

mass of the first ball, m₁ = 3 kg

initial velocity of the first ball, u₁ = 5 m/s

final velocity of the first ball, v₁ = 2.5 m/s

mass of the second ball, m₂ = 9kg

initial velocity of the second ball, u₂ = 0

final velocity of the second ball, v₂ = ?

From the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(3x5) + (9x0) = (3x2.5) + (9v₂)

15 = 7.5 + 9v₂

15 - 7.5 = 9v₂

9v₂ = 7.5

v₂ = 7.5/9

v₂ = 0.83 m/s

The second ball moves with 0.83 m/s forward.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!