Two tiny conducting spheres are identical and carry charges of -18.4 µC and +53.0 µC. They are separated by a distance of 2.73 cm. (a) What is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

-11776.36 N

This force is attractive since both charges are of opposite sign

Explanation:

Given that

Distance between the spheres = 2.73 cm =0.0273 m

where K is Coulomb's constant =

According to coulombs law we know that force between two charges is given by

This force is attractive since both charges are of opposite sign

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

it should be -8.6 cm hope this out