Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the drawstring back 60 cm from its rest position and holds it in position with a force of 166 N. If the mass of the arrow is 54 g and the "spring" is massless, what is the speed (in m/s) of the arrow immediately after it leaves the bow?

42.95m/s

Explanation:

The magnitude of the force of the spring is given as

kx = 166N

From the question, we know that x = 60cm = 0.6m

Then, the constant of the spring would be k = 166/0.6 = 276.7N/m

When the bow is pulled back 60cm, the potential energy of the arrow is.

PE = 1/2kx²

PE = 0.5 * 276.67 * 0.6²

PE = 49.8J

Finally, the speed of the arrow can be found by using principle of conservation of energy, that states that, the total energy of an isolated system remains constant and conserved over time. This means, energy is neither created nor destroyed.

1/2kx² = 1/2mv²

kx² = mv²

v² = kx²/m

v² = 276.67 * 0.6²/ 0.054

v² = 1844.5

v = 42.95m/s

the earths atmosphere is made up of nitrogen and oxygen. solids can turn into gasses through a process called sublimation. sublimation is the transition of a substance directly from the solid to the gas phase, without passing through the intermediate liquid phase.

hope this : d

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.