The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are mA = 363 kg, mB = 517 kg, and mC = 154 kg. Find the magnitude and direction of the net gravitational force acting on (a) particle A, (b) particle B, and (c) particle C.

Explanation:

For Particle A:

The net gravitational force is the sum of the two forces due to particle B and due to particle C. Both of these particles have positive direction.

    = N

For Particle B:

The net gravitational force is the sum of the two forces: due to particle A  and due to particle C. The force due to particle A is negative as its direction is to left. The force due to particle C is positive.

= N

For particle C:

The net gravitational force is the sum of two forces: due to particle A and due to particle B. Both forces are negative then,

     =

vapour or gas assuming atmospheriv pressure