Three cars (car F, car G, and car H) are moving with the same velocity when the driver suddenly slams on the brakes, locking the wheels. The most massive car is car F, the least massive is car H, and all three cars have identical tires.(a) Which car travels the longest distance to skid to a stop?b) For which car does friction do the largest amount of work in stopping the car?

a.They all travel the same distance.

B. Car F

Explanation:

A. For the three cars, we have that

ƒ = μN and since

N = F(g) = mg,

therefore ƒ = μmg.

Considering Inertia as a property of matter which increases with linearly. The more massive a car is, the more inertia carrying it forward, but also the more friction required in trying to stop it, so the two will cancel out and all three cars will stop at same distance

B.For the three cars, we have that,

w = Fd.

The force acting on the cars as they move forward is friction,

therefore w = ƒd. Since ƒ = μN and N = F(g) = mg, then,

ƒ = μmg.

Combining friction equation with the work equation gives us

w = μmgd. As μ, g, and d will be constant between equations, the greatest work done by friction will come from the car with the greatest mass.

total distance/total time

(85 + 82)/(5+3)

167/8

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