Two long, straight, parallel wires of length 3.7 m carry parallel currents of 3.6 A and 1.6 A. (a) If the wires are separated by a distance of 3.1 cm, what is the magnitude of the force between the two wires

Explanation:

Given:

Length of the parallel wires (L) = 3.7 m

Current in the first wire (I₁) = 3.6 A

Current in the second wire (I₂) = 1.6 A

Separation between the parallel wires (d) = 3.1 cm = 0.031 m  [1 cm = 0.01 m]

Both the wires will attract each with forces equal in magnitude and opposite in direction.

Now, the magnitude of the force acting between the two wires is given as:

Where,

Plug in the given values and solve for |F|. This gives,

Therefore, the magnitude of the force between the two wires is

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c) both a and b.