Physics, 13.03.2020 03:31 mackenziewright2002
Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′ separated by a distance d is |F|=K|QQ′|d2, where K=14πϵ0, and ϵ0=8.854×10−12C2/(N⋅m2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q1 = -14.5 nC , is located at x1 = -1.695 m ; the second charge, q2 = 37.0 nC , is at the origin (x = 0).
Requried:
What is the net force exerted by these two charges on a third charge q3 = 55.0 nC placed between q1 and q2 at x3 = -1.085 m in N
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Coulomb's law for the magnitude of the force F between two particles with charges Q and Q′ separated...
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