A cyclist rides 8.0 km east for 20 minutes, then he turns and heads west for 8 minutes and 3.2 km. Finally, he rides east for 16 km, which takes 40 minutes. (a) What is the final displacement of the cyclist? (b) What is his average velocity?

a) final displacement of the cyclist = 20.8km

b) average velocity = 18 .35km/hr

Explanation:

Given that,

cyclist rides 8.0 km east for 20 minutes

heads west for 8 minutes and 3.2 km

rides east for 16 km, which takes 40 minutes

The cyclist has 3 vector

v₁ = 8i km

v₂ = -3.2i km

v₃ = 16i km

The final isplacement is the sum of vector

= 8 + (-3-2) + 16

= 20.8km

final displacement of the cyclist = 20.8km

b) average velocity we have

average velocity = 18 .35km/hr

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down