In a RLC circuit, a second capacitor is connected in parallel with the capacitor previously in the circuit. What is the effect of this change on the impedance of the circuit?

Explanation:

As we know that the impedance of the circuit is given as

when we join another identical capacitor in parallel with previous capacitor in the circuit then we will have for parallel combination

so it is

now we have

Case i) if

So initially if the circuit is inductive in nature then its net impedance will decrease after this

Case ii) if

So initially if the circuit is capacitive in nature then its net impedance will increase after this

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm