Two capacitors with capacitances of 1.5 mF and 0.25 mF, respectively, are connected in parallel. The system is connected to a 50-V battery. What electrical potential energy is stored in the 1.5-mF capacitor?

Energy U = 1.875J

Explanation:

The voltage applied across the capacitors is the same and equal to 50V. The energy stored in a capacitor is given by

U = 1/2×CV²

So on substituting the required quantities into the equation we get U.

See attachment below.

show the wavelengths of a wave. show the crests of a wave.