A standing wave of the third harmonic is induced in a stopped pipe of length 1.2 m. The speed of sound through the air of the pipe is 340 m/s. How many antinodes form in the standing wave pattern in the pipe?

Answer is 3.

Explanation:

Start by putting the values in the formula i.e.

Lenght 1.2m

The speed of sound through the pipe 340m/s.

Put it in the formula and the answer is 3.

i would say

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j