A fuel pump sends gasoline from a car's fuel tank to the engine at a rate of 5.94 10-2 kg/s. The density of the gasoline is 735 kg/m3, and the radius of the fuel line is 3.10 10-3 m. What is the speed at which the gasoline moves through the fuel line

2.68 m/s

Explanation:

volume] = [mass] / [density] so the volume flow rate of the gasoline is just [mass flow rate] / density

= [5.94 * 10^-2 kg/s] / [735 kg/m^3]

= 8.08 * 10^-5 m^3 /s

The cross sectional area (A) of the fuel line of radius r is given by

A = πr² = π * (3.10* 10^-3)²

A = 3.02* 10^-5 m²

Linear flow rate = [volume flow rate] / [cross sectional area]

= [8.08 * 10^-5 m^3/s] / [3.02 * 10^-5 m^2]

= 2.68 m/s

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