An object is thrown vertically upward with an initial velocity of 10 m/sec from a height of 3 meters. In meters, find the highest point it reaches. (Round your answer to three decimal places.)

Highest point from the ground that ball reaches = 5.102

Explanation:

Formula -

v² - u² = 2as

final velocity v = 0

initial velocity u = 10m/s

acceleration a = g (gravity)=9.8

distance s = 3m+x (x is the height after 3m that object reaches)

0-(10)² = 2 (-g)*(3+x)

-100 = -2g*(3=x)

(3+x)=100/2g

3+x = 100/2*9.8 = 100/19.6 = 5.102

x=5.102-3

x=2.102

So, the highest point will be

3+x = 3+2.102

=5.102m

area of focus