Water is circulating through a closed system of pipes in a two floor apartment. On the first floor, the water has a gauge pressure of 3.70 105 Pa and a speed of 2.4 m/s. However, on the second floor, which is 3.6 m higher, the speed of the water is 3.5 m/s. The speeds are different because the pipe diameters are different. What is the gauge pressure of the water on the second floor

The value of gauge pressure at outlet = -38557.224 pascal

Explanation:

Apply Bernoulli' s Equation

+ + = + + --------------(1)

Where

=  Gauge pressure at inlet = 3.70105 pascal

= velocity at inlet =  2.4

= Gauge pressure at outlet = we have to calculate

= velocity at outlet = 3.5

= 3.6 m

Put all the values in equation (1) we get,

⇒ + = + + 3.6

⇒ 0.294 = + 0.6244 + 3.6

⇒ = 0.294 - 0.6244 - 3.6

⇒ = - 3.9304

⇒ = - 38557.224 pascal

This is the value of gauge pressure at outlet.

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

option number c is the right answer.