An electric motor rotating a workshop grinding wheel at a rate of 153 rev/min is switched off. Assume constant angular deceleration of magnitude 1.93 rad/s 2 . Through how many revolutions does the wheel turn before it finally comes to rest? Answer in units of rev.

force tends to be low and long diustance masses are high

a is the best answer your welcome

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down