A .15 kg ball is dropped from the top of a 150 m building. What is the kinetic energy of the ball when it passes the 16th floor at a height of 63 m?

Explanation:

Distance convered 150m to 60m above the ground = 150- 60=87m

final velocity to cover 87 m as follows:

v^2 =u^2 + 2gh

v^2= 0^2 + 2×9.8××87

v^2=1705.2

v = ✓1705.2

v=41.29 m/s

kinetic energy of the ball as follows:

kinetic energy= 1/2mv^2

E =1/2×15×41.29^2

E =12.8KJ

b.

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