A ball is thrown from 1 m above the ground. The initial velocity is 20 m/s at an angle of 40 degrees above the horizontal. What is the maximum height of the ball above the ground

9.4 m

Explanation:

This is a projectile motion. The maximum height above the level projection is given by

is the initial velocity, is the angle of projection above the horizontal and is the acceleration of gravity.

The maximujm height above the ground is 1 m + 8.4 m = 9.4 m

answer( sicar );