If the electric field has a magnitude of 440 N/C and the magnetic field has a magnitude of 0.19 T , what speed must the particles have to pass through the selector undeflected?

2315.8 m/s

Explanation:

For the charged particle to pass through this field undeflected, the electric force and the magnetic force acting on it must be equal

Electric force = Magnetic force

Electric force = Eq

Magnetic force = qvB

qvB = Eq

v = (E/B)

E = 440 N/C, B = 0.19 T

v = (440/0.19)

v = 2315.8 m/s

the answer is b ) square root of 5

f is prop to m1xm2 double m1 double force