The planet Krypton has a mass of 4 × 1023 kg and radius of 1.1 × 106 m. What is the acceleration of an object in free fall near the surface of Krypton? The gravita- tional constant is 6.6726 × 10−11 N · m2/kg2. Answer in units of m/s2.

Explanation:

From the Newton's Law of Universal Gravitation, we have that the acceleration due to gravitational force near an object of mass M, is given by:

Where g is the acceleration due to gravity, G is the gravitational constant, and R is the distance between the objects.

In this case, we have the given values for planet Krypton:

This means that the acceleration of an object in free fall near the surface of Krypton is of 22.0m/s².

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.