A 0.62 kg ball is moving horizontally with a speed of 4.7 m/s when it strikes a vertical wall. The ball rebounds with a speed of 2.6 m/s. What is the magnitude of the change in linear momentum of the ball

The change in momentum of the ball is 4.52 kg-m/s.

Explanation:

Given that,

Mass of the ball, m = 0.62 kg

Initial speed of the ball, u = 4.7 m/s

The ball rebounds with a speed of 2.6 m/s, v = -2.6 m/s

We need to find the magnitude of the change in linear momentum of the ball. We know that the linear momentum is given by :

p = mv

So, the change in momentum is :

So, the change in momentum of the ball is 4.52 kg-m/s. Hence, this is the required solution.

80cm/s.

24cm/s.

53.3cm/s.