A small object with mass m = 0.0900 kg moves along the +x-axis. The only force on the object is a conservative force that has the potential-energy function U(x) = −αx^2 + βx^3, where α= 5.00 J/m^2 and β = 0.300 J/m^3. The object is released from rest at small x. When the object is at x = 4.00 m, what are its:
(a) speed and (b) acceleration (magnitude and direction)?
(c) What is the maximum value of x reached by the object during its motion?

Since you have not included the experiment situation and the data, of course, i can not give you specific details about it. but i can you with this question.1) i will assume that the motion is projectile (parabolic) motion.2) yes, the horizontal distance depends on the horizontal velocity as, naming vx the horizontal velocity and t the time, it is: x = vx × t3) now, observe that the flight time depends on the vertical velocity as, naming voy the initial vertical velocity, t the time and y the vertical distance before reaching the ground: y = yo + voy×t - gt² / 2.the higher the initial vertical velocity (voy) the longer the object will be flying and so t will be higher in the equation for the horizontal distance.that explains the relationship between the horizontal distance and the horizontal velocity.

Despite their crazy structure, human bones are surprisingly good!