When Woods hits a 0.04593 kg golf ball, the golf ball is usually traveling around 281 kilometers per hour. What average force does he exert on a golf ball if the club head and golf ball are in contact for 0.030 seconds?

128.9 N

Explanation:

The force exerted on the golf ball is equal to the rate of change of momentum of the ball, so we can write:

where

F is the force

is the change in momentum

is the time interval

The change in momentum can be written as

where

m = 0.04593 kg is the mass of the ball

u = 0 is the initial velocity of the ball

is the final velocity of the ball

Substituting into the original equation, we find the force exerted on the golf ball:

i think the answer would be reserve.