How much thermal energy is needed to raise the temperature of 4.0 kg of water from 25°C to 75°C?

Q= 840,000 J

Explanation: We will use the formula for heat to solve this problem Q= mc∆T, where the specific heat or "c" of water is 4200 J/kg°C. The change in temperature ∆T is equal to ∆T = ( 75°C-25°C) = 50°C

Q= 4.0 kg ( 4200 J/kg°C) ( 50°C)

= 840,000J

Cancel out the units of kg and °C so the remaining unit is in joules.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

are you like autistic or something?

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