A 6500 kg satellite orbits a planet. If its distance to the center of the planet is 9e6 m and its speed is 6.7e3 m/s, what is the gravitational force between the satellite and the planet

the gravitational force between the satellite and the planet is 32.4  * 10³N

Explanation:

It is given that,

Mass of the satellite, m = 6500 kg

Speed of the satellite, v = 6.7 × 10³ m/s

distance to the center of the planet = 9  × 10⁶m

Let F is the magnitude of the gravitational force exerted on the satellite by the planet. The centripetal force is equal to the gravitational force. It is equal to :

= 32.4  * 10³N

the gravitational force between the satellite and the planet is 32.4  * 10³N

Complete Question

The complete question is shown on the first uploaded image

Option D is the Answer

Explanation:

The formula for the velocity of the satellite is

      R is the distance to the center o the planet =

     G is the gravitational constant which is equal to  

     M is the mass of the planet

 Making M the subject of the formula we have

The formula for the gravitational force between two object

Where

this could be newton#'s law of cooling. the cooling curve is exponential