The quantity of charge through a conductor is modeled as Q = (3.00 mC/s4)t4 − (2.00 mC/s)t + 9.00 mC. What is the current (in A) at time t = 4.00 s? A

The current at time t = 4.00 s is 0.766 A.

Explanation:

Given that,

The quantity of charge through a conductor is modeled as :

We need to find the current (in A) at time t = 4.00 s. We know that the rate of change of electric charge is called electric current. It is given by :

At t = 4 s

So, the current at time t = 4.00 s is 0.766 A. Hence, this is the required solution.

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.