Water vapor is cooled in a closed, rigid tank from T1 = 480°C and p1 = 100 bar to a final temperature of T2 = 320°C. Determine the final specific volume, v2, in m3/kg, and the final pressure, p2, in bar.

v1 = v2 = 0.0347m³/kg the tank is rigid (constant volume)

P2 = 78.8bar

Explanation:

Assuming ideal gas behavior, the relationship holds for the water vapor

PV = RT/M

Where P = pressure in the tank

V = Specific volume in m³/kg

R = gas constant = 8.314 J/mol•K

T = absolute temperature in K

M = molar mass in kg/mol

The detailed solution steps can be found below in the attachment.

V2 = V1 because the tank is rigid so it is a constant volume process. Also at the final temperature the water molecules are still in the gaseous phase so V2 is still the same as v1.

how do you expect people to write a full essay for you and only get 13 pt you need to give more dude make a change

explanation:

as the height from which the ruler was dropped increased, the speed of the ruler at ryan's hand increased.