A 60 W light bulb is powered by a connection to a wall outlet with 120 V across the plug terminals. a) What is the current passing thru this resistor?

The current through the resistor is 0.5 A

Explanation:

Given;

power of the light bulb = 60 W

voltage in the wall outlet across the plug terminals = 120 V

power of the light bulb is the product of voltage in the wall outlet across the plug terminals and the current passing through the resistor.

power = voltage x current

Therefore, for a  60 W light bulb powered by a connection to a wall outlet with 120 V across the plug terminals, the current passing through the resistor is 0.5 A

0.5 A

Explanation:

Current: The can be defined as the rate of flow of charge around a circuit. The S.I unit of current is Ampere(A)

Using,

P = VI Equation 1

Where P = Power rating of the bulb, V = Voltage of the wall outlet, I = Current passing through the resistor.

Make I the subject of the equation

I = P/V Equation 2

Given: P = 60 W, V = 120 V.

Substitute into equation 2

I = 60/120

I = 0.5 A.

Hence the  current passing through the resistor = 0.5 A

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

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