The electric force on two charges, Q1 and Q2, that are separated by a distance d is given by F. if you increase their distance to 5d, what is the electric force?

F/ 25

Explanation: The electro static force between 2 charges follows an inverse square law.

F1×(d1)² = F2 × (d2)²

From the question, F1 =F, d1 =d and d2 = 5d, we are to find F2

F×d² = F2 × (5d)²

F×d² = F2 × 25d²

F2 = F × d²/25d²

F2 = F/ 25

heat the gas and measure the pressure

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