A 23000 kg railroad freight car collides with a stationary caboose car. They couple together, and 18 percent of the initial kinetic energy is lost. What is the mass of the caboose

5048.78kg

Explanation:

Given and , From the law of conservation of momentum we have:

Hence,

Since 18% of initial is lost:-

Therefore, by substituting with :

The mass of the caboose is 5048.78kg

the answer would be c

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft