A 3.92 cm tall object is placed in 31.3 cm in front of a convex mirror. The focal
length is 12.7 cm. What is the magnification of the image?

0.29

Explanation:

We can find the position of the image by using the mirror equation:

where:

f is the focal length of the mirror

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For the mirror in this problem:

f = -12.7 cm (the focal length of a convex mirror is negative)

p = 31.3 cm (distance of the object)

Solving for q, we find the position of the image:

And so, the magnification of the image is:

And substituting,

Which means that the image is upright (positive sign) and diminished (M is smaller than 1).

when it gains or loses electrons

close lines strong magnet less close weaker