If 100mL of boiling water is combined with 25g of ice, what will its
temperature be when equilibrium is reached?
You’ll get brainlest but I need it rn rn

Explanation:

Assume that all the heat released by the boiling water is absorbed by the ice.

1. Heat released by the 100 mL liquid boiling water

2. Heat absorbed by the 25 g of ice

a) Heat to melt the ice

b) Heat to increase of liquid water from 0ºC until the equilibrium temperature

3. Set your final equation:

Solve:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

the inner core.

good luck: )

klicker