Please help I'm desperate. and please explain how need to show work!
a car going 33.8 m/s has its brakes appied. if the brakes apply 3.87 N of force for 4.92 m what was the cars velocity after braking?

33.2 m/s

Explanation:

In order to solve this problem, we need to know the mass of the car.

Here, we assume that the mass of the car is

m = 1 kg

Then, we can apply the work-energy theorem, which states that the work done on the car by the braking force is equal to the change in its kinetic energy:

where:

F = -3.87 N is the force applied by the brakes (negative because its direction is opposite to the motion of the car)

d = 4.92 m is the displacement of the car

u = 33.8 m/s is the initial velocity of the car

v is the final velocity of the car

Therefore, solving for v, we find:

where's the following? you gotta add it to know what the choices are

explanation:

im guessing the west of station b