A car travels along a horizontal road which is an arc of radius 125m. the greatest speed at which the car can travel without sleeping is 42km/hr .find the coefficient of friction between the tyre and the ground

The coefficient of friction between the Tyre and the ground is 0.11

Explanation:

Given:

Radius of the track (r)=125 m.

Speed with which the car travels (v) =42 km/hr

                                                             =11.67 m/s

To Find:

Coefficient of friction between the Tyre and the ground.

Formula to be used:

We know that,Frictional force is equal to centripetal force

Frictional force=μmg

therefore 1.08 m=μmg

Cancelling "m" on both sides we get,

μ=1.08/g=1.08/9.8

=0.11

Thus the coefficient of friction between the Tyre and the ground is 0.11

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down