A uniform magnetic field passes through a horizontal circular wire loop at an angle 16.2 ° from the normal to the plane of the loop. The magnitude of the magnetic field is 2.95 T , and the radius of the wire loop is 0.240 m . Find the magnetic flux Φ through the loop.

Magnetic flux,

Explanation:

Given that,

The magnitude of the magnetic field is 2.95 T

Radius of the circular wire, r = 0.240 m

A uniform magnetic field passes through a horizontal circular wire loop at an angle 16.2 ° from the normal to the plane of the loop. The magnetic flux is given by the formula as :

So, the magnetic flux Φ through the loop is . Hence, this is the required solution.

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snell's law

refractve index = sin incidence / sin refraction