Physics, 07.03.2020 04:33 angieinthehouse45

You are looking for a personal trainer to help you make gains. How can you be sure that your personal trainer is certified by a professional organization

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As long as there is a sort of "certified" or "registered" credential, one can be sure he or she is qualified and trained appropriately. The credentials should show how qualified he or she is.

Explanation:

Certificates and credentials are very important in selling your products or services. Everyone wants to see your credentials before you are being trusted as a trainer. Therefore if the trainer shows his or her credentials, he or she can trusted.

Answer from: reeeg38

Explanation:

There are a number of legitimate and widely recognized certificates that my personal trainer may possess and I will be sure that he/she is certified by a professional organization. Let's assume that I am currently in the United States of America and searching for a personal trainer;

*** One of the ways to know if he or she is approved to train is if the person possesses a kind of registered or certified credential. This will make me to be rest assured that I am going to be handled by a professional who is qualified.

I will ask my personal trainer if the American council on exercise (A .C .E) certified him or her to train people.

I can also be sure that my potential personal trainer is qualified if he or she has received approval and is certified by the American college of sports medicine.

I may also ask my trainer if the national commission for certifying agencies certified him or her.

Answer from: Quest

Charles darwin marked the difference among countless finches on the galápagos islands.i hope i !
Iwill mark as the brainliest answer

Answer from: Quest

we have been given a quadratic function $f(x)=(x-5)^{2} +2$ and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is $[2,\infty)$ .

if we restrict the domain of this function to either $(-\infty,5]$ or $[5,\infty)$ , it will become one to one function.

let us know find its inverse.

$y=(x-5)^{2}+2$

upon interchanging x and y, we get:

$x=(y-5)^{2}+2$

let us now solve this function for y.

$(y-5)^{2}=x-2\\ y-5=\pm \sqrt{x-2}\\ y=5\pm \sqrt{x-2}\\$

hence, the inverse function would be $f^{-1}(x)=5+\sqrt{x-2}$ if we restrict the domain of original function to $[5,\infty)$ and the inverse function would be $f^{-1}(x)=5-\sqrt{x-2}$ if we restrict the domain to $(-\infty,5]$ .

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