A projectile is launched from the top of a tower of height 30m with an initial velocity of 20m/s at an angle of 30degree above the horizontal. Calculate 1) the time of flight to the ground 2) the velocity and impact

Explanation:

u = initial velocity = 20m/s

h = Height = 30m

Theta = 30°

g = acceleration due to gravity =9.8m/s^2

Time of flight (T) = total time taken by an object reach its maximum height and return to the ground.

T =( 2*u*sin(theta)) ÷g

T = (2*20*sin(30°))÷9.8

T = (40 * 0.5) ÷ 9.8

T = 20 ÷9.8

T = 2.04s

Velocity (v)

v = sqrt(2gh)

v = sqrt(2*9.8*30)

v = sqrt(588)

v = 24.25m/s

(75°f − 32) × 5/9 = 23.889°c

its a 5.5 n

glad that