A boxed 15.0kg computer monitor is dragged by friction 5.50m up along the moving surface of a conveyor belt inclined at an angle of 36.2 degrees above the horizontal. If the monitor's speed is a constant 2.20cm/s , how much work is done on the monitor by friction, gravity, and the normal force of the conveyor belt?

a) W friction = J

b) W gravity = J

c) W N = J

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

wavelegth as in spectrum red oygbiv

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.