Find the net charge of a system consisting of 6.16×106 electrons and 7.68×106 protons. Express your answer using three significant figures. Qnet = 2.43×10−13 C

2.43 * 10^(-13) C

Explanation:

The net charge of the system is given as the sum of the total charge of the electrons and the charge of the protons.

Qnet = (Ne * Qe) + (Np * Qp)

Ne = number of electrons = 6.16 * 10^6

Np = number of protons = 7.68 * 10^6

Charge of an electron = -1.602 * 10^(-19) C

Charge of a proton = 1.602 * 10^(-19) C

Qnet = (6.16 * 10^6 * -1.602 * 10^(-19)) + (7.68 * 10^6 * 1.602 * 10^(-19))

Qnet = -9.87 * 10^(-13) + 12.30 * 10^(-13)

Qnet = 2.43 * 10^(-13) C

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas