The resistivity of a semiconductor can be modified by adding different amounts of impurities. A rod of semiconducting material of length L and cross-sectional area A lies along the x-axis between x=0 and x=L. The material obeys Ohm's law, and its resistivity varies along the rod according to rho(x)=rho0exp(−x/L). The end of the rod at x=0 is at a potential V0 greater than the end at x=L.1) Graph the function rho(x) for values of x between x=0 and x=L.2) Graph the function E(x) for values of x between x=0 and x=L.3) Graph the function V0(x) for values of x between x=0 and x=L. I answered the previous parts correctly but can't plot the graphs correctly so please help! I need exact values for x and y. Below I will post my answeres:Part AFind the total resistance of the rod. Express your answer in terms of the given quantities and appropriate constants. R = .632 (Lrho_0/A)SubmitMy AnswersGive UpCorrectPart BFind the current in the rod. Express your answer in terms of the given quantities and appropriate constants. I = V_0A/.632rho_0LSubmitMy AnswersGive UpCorrectPart CFind the electric-field magnitude E(x) in the rod as a function of x. Express your answer in terms of the given quantities and appropriate constants. E(x) = (V_0*e^−x/L)/.632LSubmitMy AnswersGive UpCorrectPart DFind the electric potential V(x) in the rod as a function of x. Express your answer in terms of the given quantities and appropriate constants. V(x) = V_0((e^−x/L)−(e^−1))/.632